16t^2+3t=153

Solution for 16t^2+3t=153 equation:

16t^2+3t=153

We move all terms to the left:

16t^2+3t-(153)=0

a = 16; b = 3; c = -153;
Δ = b2-4ac
Δ = 32-4·16·(-153)
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9801}=99$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-99}{2*16}=\frac{-102}{32}
=-3+3/16
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+99}{2*16}=\frac{96}{32}
=3
$